RÚT GỌN :
A= $\frac{4^{5}. 9^{4}-2. 6^{9}}{2^{10}.3^{8}+6^{8}. 20}$
B=$\frac{8^{10}+4^{10}}{8^{4}+4^{11}}$
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#2
Posted 09-07-2016 - 19:02
thinhnarutop
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$A=\frac{2^{10}.3^{8}-2^{10}.3^{9}}{2^{10}.3^{8}+2^{10}.3^{8}.5}=\frac{-1}{3}$
$B=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{18}+2^{8}}{1+2^{10}}=256$
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#3
Posted 10-07-2016 - 08:47
thuhanh2984
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$A=\frac{2^{10}.3^{8}-2^{10}.3^{9}}{2^{10}.3^{8}+2^{10}.3^{8}.5}=\frac{-1}{3}$
$B=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{18}+2^{8}}{1+2^{10}}=256$
giải thích cho em chỗ $2.6^{9}$ sao thành $2^{10}.3^{9}$ ạ
Edited by thuhanh2984, 10-07-2016 - 08:49.
#4
Posted 10-07-2016 - 08:51
thinhnarutop
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giải thích cho em chỗ $2.6^{9}$ sao thành $2^{10}.3^{9}$ ạ
Ta có: $2.6^{9}=2.2^{9}.3^{9}=2^{10}.3^{9}$
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