Chủ đề này có 2 trả lời

[hanhtrang123]

1, $x-1+\sqrt{x+1}+\sqrt{2-x}=x^{2}+\sqrt{2}$

2, $\left ( x-1 \right )\left ( 2\sqrt{x-1}+3\sqrt[3]{x+6} \right )=x+6$

3, $\left ( 4x-1 \right )\left ( \sqrt{x+3} +\sqrt[3]{3x+5}\right )=4x+8$

4, $\left ( \sqrt{4x^{4}-12x^{3}+9x^{2}+16}-2x^{3}+3x \right )\left ( \sqrt{x+3}+\sqrt{x-1} \right )=8$

5, $5\left ( 1+\sqrt{1+x^{3}} \right )=x^{2}\left ( 4x^{2} -25x+18\right )$

6, $\frac{\sqrt{x+1}-2}{\sqrt[3]{2x+1}-3}=\frac{1}{x+2}$

7, $\sqrt{x+1}=\frac{x^{2}-x-2\sqrt{2x+1}}{\sqrt[3]{2x+1}-3}$

8, $\frac{x^{2}+2x-8}{x^{2}-2x+3}=\left ( x+1 \right )\left ( \sqrt{x+2}-2 \right )$

9, $\sqrt{5+x}+\sqrt{1-x}+\sqrt{5-4x-x^{2}}=\frac{x}{2}+\sqrt{x+6}$

10, $3^{x}+5^{x}=6x+2$

11, $3^{x}\left ( 2x-1 \right )=2x+1$

12, $2^{2x^{2}-6x+2}=\frac{2x+1}{\left ( x-1 \right )^{2}}$

13, $2^{\frac{1-x^{2}}{x^{2}}}-2^{\frac{1-2x}{x^{2}}}=\frac{1}{2}-\frac{1}{x}$

14, $2^{x-1}-2^{x^{2}-x}=\left ( x-1 \right )^{2}$

[thuylinhnguyenthptthanhha]

 

7, $\sqrt{x+1}=\frac{x^{2}-x-2\sqrt{2x+1}}{\sqrt[3]{2x+1}-3}$

 

tr ạ, sao lắm vầy bạn 

ĐK:...........

PT $\Leftrightarrow \sqrt{x+1}+2=\frac{x^2-x-6}{\sqrt[3]{2x+1}-3}$

$\Leftrightarrow \frac{(x+2)(\sqrt{x+1}-2)}{\sqrt[2]{2x+1}-3}=1$

$\Leftrightarrow (2x+1)+\sqrt[3]{2x+1}=(x+1)\sqrt{x+1}+\sqrt{x+1}$

Xét hàm $f(t)=t^3+t$ đồng biến trên R

$\rightarrow $ PT $\Leftrightarrow \sqrt{x+1}=\sqrt[3]{2x+1}$

$\Rightarrow \left\{ \begin{array}{l} x\geq \frac{-1}{2}\\ (2x+1)^2=(x+1)^3 \end{array} \right.$

$\rightarrow ..............$

Bạn lm tiếp nhak ~~

[thuylinhnguyenthptthanhha]

 

8, $\frac{x^{2}+2x-8}{x^{2}-2x+3}=\left ( x+1 \right )\left ( \sqrt{x+2}-2 \right )$

 

http://diendantoanho...-2x3x1sqrtx2-2/