a^4+b^4+c^4>= (a+b+c)^4/27
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Started By linhhd, 30-10-2016 - 11:27
#1
Posted 30-10-2016 - 11:27
#2
Posted 30-10-2016 - 11:51
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Sử dụng BĐT Holder:
$27(a^{4}+b^{4}+c^{4})=(1+1+1)(1+1+1)(1+1+1)(a^{4}+b^{4}+c^{4})\geq (a+b+c)^{4}$ (Đ.P.C.M)
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