Tìm x
a) (4x + 1)(12x - 1)(3x + 2)(x - 1)=4
b) 4x2 - 5x + 3= (1-2x)căn(4x2 - 6x +3)
c) (3x+4)(x+1)(6x+7)2=6
d) (4x -1)căn(x2 + 1)=2x2+2x+1
e) 3x2+21x+18+2 căn(x2+7x+7)=2
Giúp mình vs
Tìm x
a) (4x + 1)(12x - 1)(3x + 2)(x - 1)=4
b) 4x2 - 5x + 3= (1-2x)căn(4x2 - 6x +3)
c) (3x+4)(x+1)(6x+7)2=6
d) (4x -1)căn(x2 + 1)=2x2+2x+1
e) 3x2+21x+18+2 căn(x2+7x+7)=2
Giúp mình vs
$\Re \varepsilon \alpha \imath \ast \Cap \alpha \wp \Re \zeta \wp \triangleright \mathbb{C}\xi$
c)
$PT\Leftrightarrow (6x+6)(6x+7)^{2}(6x+8)=72$
Đặt 6x+7=a
$\Rightarrow (a-1)a^{2}(a+1)=72$
$(a^{2}-1)a^{2}=72$
$a=3;-3$
suy ra x
Tìm x
a) (4x + 1)(12x - 1)(3x + 2)(x - 1)=4
b) 4x2 - 5x + 3= (1-2x)căn(4x2 - 6x +3)
c) (3x+4)(x+1)(6x+7)2=6
d) (4x -1)căn(x2 + 1)=2x2+2x+1
e) 3x2+21x+18+2 căn(x2+7x+7)=2
Giúp mình vs
b) $4x^{2}-5x+3=(1-2x)\sqrt{4x^{2}-6x+3}<=>(4x^{2}-5x+3)=(4x^{2}-4x+1)(4x^{2}-6x+3)<=>16x^{4}-40x^{3}+49x^{2}-30x+9=16x^{4}-40x^{3}+40x^{2}-18x+3<=> 9x^{2}-12x+6=0...$
d) $(4x-1)\sqrt{x^{2}+1}=2x^{2}+2x+1<=> 2(4x-1)\sqrt{x^{2}+1}=4x^{2}+4x+2<=> 2(4x-1)\sqrt{x^{2}+1}=4(x^{2}+1)+(4x-1)-1$
Đặt $\sqrt{x^{2}+1}=a,4x-1=b(a\geq 0)=> 2ab=4a^{2}+b-1<=>(2a-1)(2a+1-b)=0...$
e) $<=> 3(x^{2}+7x+7)+2\sqrt{x^{2}+7x+7}-5=0...$
Bài viết đã được chỉnh sửa nội dung bởi Tea Coffee: 24-07-2017 - 08:06
Treasure every moment that you have!
And remember that Time waits for no one.
Yesterday is history. Tomorrow is a mystery.
Today is a gift. That’s why it’s called the present.
Treasure every moment that you have!
And remember that Time waits for no one.
Yesterday is history. Tomorrow is a mystery.
Today is a gift. That’s why it’s called the present.
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