giải phương trình $4\sqrt{x+3}-\sqrt{x-1}=x+7$
Edited by tpdtthltvp, 11-08-2017 - 23:39.
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Posted 04-08-2017 - 14:34
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giải phương trình 4căn(x+3)-căn(x-1)=x+7
Ta có:$4\sqrt{x+3}-\sqrt{x-1}=x+7<=> x+3-4\sqrt{x+3}+4+\sqrt{x-1}<=>(\sqrt{x+3}-2)^{2}+\sqrt{x-1}=0$
Dấu = xảy ra khi và chỉ khi x=1
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