Cho tam giác ABC điểm I và $x, y, z \epsilon R, x+y+z\neq 0, x, y, z> 0$ thoả mãn
$x\overrightarrow{IA}+y\overrightarrow{IB}+z\overrightarrow{IC}=\overrightarrow{0}$
chứng minh rằng $\frac{x}{S_{IBC}}=\frac{y}{S_{ICA}}=\frac{z}{S_{IAB}}$
$\frac{x}{S_{IBC}}=\frac{y}{S_{ICA}}=\frac{z}{S_{IAB}}$
Started By tiendungthachthat, 07-10-2017 - 09:19
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