Đề thi tuyển sinh vào lớp 10 chuyên toán Hoàng Văn Thụ tỉnh Hòa Bình năm học 2018-2019 (toán chung)
Started By NguyenHoaiTrung, 05-06-2018 - 18:33
#1
Posted 05-06-2018 - 18:33
#2
Posted 08-06-2018 - 06:15
V)2)$P.13=(x^{2}+y^{2})(9+4)\geq (3x+2y)^{2}=(x+2x+2y)^{2}\geq (3+2.5)^{2}=13^{2}=>P\geq 13<=>x=3,y=2$
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#3
Posted 19-06-2018 - 13:56
#4
Posted 02-07-2018 - 21:19
Câu V (1)
x2+2y2+3xy+2x+2y-3=0
x(x+y) + 2y(x+y) + 2(x+y)=3
(x+y)(x+2y+2)=3
Đến đay đơn giản rồi ......
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