Cho hình chóp $O.ABC$, có $OA=OB=OC$, $AOB=BOC=60^0, AOC=90^0$.Chứng minh rằng: $(ABC) \perp (AOC)$
Cho hình chóp $O.ABC$, có $OA=OB=OC$
Started By Drago, 30-09-2018 - 17:06
#1
Posted 30-09-2018 - 17:06
$\mathbb{VTL}$
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