Cho (AB < AC), trung tuyến AM, D$\in$ BC sao cho $\widehat{BAD}=\widehat{CAM}$. Chứng minh $\frac{BD}{CD}=(\frac{AB}{AC})^{2}$
Chứng minh $\frac{BD}{CD}=(\frac{AB}{AC})^{2}$
Started By Too123, 08-03-2019 - 20:19
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