Thi hoc sinh gioi Belarussia 1959.
#1
Đã gửi 29-10-2010 - 18:29
$ \dfrac{x^2 - yz }{X(1-yz)} = \dfrac{y^2 - zx}{y(1-zx)}$ (voi $ x $ $y$, $xyz$ $ 0$ ,$ yz$ $1$ ,$ xz$ $1$ )
CMR: $ x+ y +z = \dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c}$
It is difficult to say what is impossible, for the dream of yesterday is the hope of today and the reality of tomorrow
#2
Đã gửi 29-10-2010 - 18:31
cho ba so x,y,z thoa man :
$ \dfrac{x^2 - yz }{X(1-yz)} = \dfrac{y^2 - zx}{y(1-zx)}$ (voi $ x $ $y$, $xyz$ $ 0$ ,$ yz$ $1$ ,$ xz$ $1$ )
CMR: $ x+ y +z = \dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c}$
It is difficult to say what is impossible, for the dream of yesterday is the hope of today and the reality of tomorrow
#3
Đã gửi 29-10-2010 - 18:33
cho ba so x,y,z thoa man :
$\dfrac{x^2-yz}{X(1-yz)} = \dfrac{y^2 - zx}{y(1-zx)}$ (voi $ x $ $y$, $xyz$ $ 0$ ,$ yz$ $1$ ,$ xz$ $1$ )
CMR: $ x+ y +z = \dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c}$
It is difficult to say what is impossible, for the dream of yesterday is the hope of today and the reality of tomorrow
#4
Đã gửi 29-10-2010 - 18:37
$a,b,c$ ở đâu ra vậy???????cho ba so x,y,z thoa man :
$ \dfrac{x^2 - yz }{x.(1-yz)} = \dfrac{y^2 - zx}{y(1-zx)}$ (voi $ x \neq y, xyz \neq 0, yz \neq 1 , xz \neq 1$ )
CMR: $ x+ y +z = \dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c}$
Bài viết đã được chỉnh sửa nội dung bởi dark templar: 29-10-2010 - 18:38
#5
Đã gửi 29-10-2010 - 18:45
It is difficult to say what is impossible, for the dream of yesterday is the hope of today and the reality of tomorrow
1 người đang xem chủ đề
0 thành viên, 1 khách, 0 thành viên ẩn danh