$$\dfrac{\sqrt{a^3c}}{\sqrt{b^3a}+bc}+ \dfrac{\sqrt{b^3a}}{\sqrt{c^3a}+ca}+\dfrac{\sqrt{c^3b}}{\sqrt{a^3c}+ab}$$ với $a,b,c>0$
Edited by HD.Nhat, 07-12-2011 - 21:47.
Tìm $\min\left(\dfrac{\sqrt{a^3c}}{\sqrt{b^3a}+bc}+ \dfrac{\sqrt{b^3a}}{\sqrt{c^3a}+ca}+\dfrac{\sqrt{c^3b}}{\sqrt{a^3c}+ab}\right)$
Started By HD.Nhat, 07-12-2011 - 21:22
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Posted 07-12-2011 - 21:22
HD.Nhat
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Binh nhì
Tìm giá trị nhỏ nhất của:
$$\dfrac{\sqrt{a^3c}}{\sqrt{b^3a}+bc}+ \dfrac{\sqrt{b^3a}}{\sqrt{c^3a}+ca}+\dfrac{\sqrt{c^3b}}{\sqrt{a^3c}+ab}$$ với $a,b,c>0$
$$\dfrac{\sqrt{a^3c}}{\sqrt{b^3a}+bc}+ \dfrac{\sqrt{b^3a}}{\sqrt{c^3a}+ca}+\dfrac{\sqrt{c^3b}}{\sqrt{a^3c}+ab}$$ với $a,b,c>0$
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