$2(a+b+c)-abc\leqslant 10$
Edited by L Lawliet, 04-09-2012 - 20:52.
CMR: $2(a+b+c)-abc\leqslant 10$
Started By khanhhx, 04-09-2012 - 20:41
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#1
Posted 04-09-2012 - 20:41
khanhhx
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Cho $a,b,c \in R$: $a^2+b^2+c^2=9$. CMR:
$2(a+b+c)-abc\leqslant 10$
$2(a+b+c)-abc\leqslant 10$
#2
Posted 05-09-2012 - 20:14
Secrets In Inequalities VP
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Đây http://diendantoanho...ight-leq-10abc/
Edited by Secrets In Inequalities VP, 05-09-2012 - 20:14.
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