mn giúp vs ạk
b1
$\frac{1}{1-x^{2}}> \frac{3x}{\sqrt{1-x^{2}}}-1$
b2
$4\left ( x+1 \right )^{2}< \left ( 2x+10 \right )\left ( 1-\sqrt{3+2x} \right )^{2}$
b3
$\sqrt{2x^{2}+8x+6}+\sqrt{x^{2}+3x+2}\geq 2(x+1)$
b1:
Đk :1-x^2 >0 => $-1\leq x\leq 1$
$\frac{1}{1-x^2}> \frac{3x}{\sqrt{1-x^2}}-1$
<=> $\frac{2-x^2}{\sqrt{1-x^2}}> 3x$
<=> $2-x^2> 3x\sqrt{1-x^2}$
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