Cho x,y,z dương thõa mãn :xy+yz+xz=1.Chứng minh rằng:
x(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?y^2)(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?z^2)+y(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?x^2)(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?z^2)+z(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?x^2)(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?y^2) http://dientuvietnam.net/cgi-bin/mimetex.cgi?\dfrac{4\sqrt{3}}{9}
hay đây
Started By dungCT, 26-11-2005 - 10:06
#1
Posted 26-11-2005 - 10:06
PHONG TRUNG CHI THẦN
#2
Posted 26-11-2005 - 10:13
Bài này dùng lượng giác là được. Hình như là một bài thi của TQ thì phải
The only way to learn mathematics is to do mathematics
#3
Posted 23-05-2006 - 17:25
mot bai don gian nhin dieu kien la biet dung luong giac roiCho x,y,z dương thõa mãn :xy+yz+xz=1.Chứng minh rằng:
x(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?y^2)(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?z^2)+y(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?x^2)(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?z^2)+z(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?x^2)(1-http://dientuvietnam.net/cgi-bin/mimetex.cgi?y^2) http://dientuvietnam.net/cgi-bin/mimetex.cgi?\dfrac{4\sqrt{3}}{9}
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