xet tat ca cac ham so bac 2 y=a$x^{2}$+bx+c voi a<b va y>0 voi moi x. cm
$\frac{a+b+c}{b-a}$> hoac=3
$\frac{a+b+c}{b-a}$> hoac=3
Started By thangnhoc9x, 26-02-2013 - 11:16
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