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Hanoi Open Mathematical Competition 2013 - Junior Section


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#1
DarkBlood

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Question 1. Write $2013$ as a sum of $m$ prime number. The smallest value of $m$ is:

$A.\ 2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B.\ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C.\ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D.\ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E.$ None of the above.

 

 

Question 2. How many natural numbers $n$ are there so that $n^2+2014$ is a perfect square?

$A.\ 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B.\ 2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C.\ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D.\ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E.$ None of the above.

 

 

Question 3. The largest integer not exceeding $[(n+1)\alpha]-[n\alpha],$ where $n$ is a natural number, $\alpha =\frac{\sqrt{2013}}{\sqrt{2014}},$ is:

$A.\ 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B.\ 2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C.\ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D.\ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E.$ None of the above.

 

 

Question 4. Let $A$ be an even number but not divisor by 10. The last two digits of $A^{20}$ are:

$A.\ 46\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B.\ 56 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C.\ 66 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D.\ 76 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E.$ None of the above.

 

 

Question 5. The number of integer solutions $x$ of the equation below.

$(12x-1)(6x-1)(4x-1)(3x-1)=330$

$A.\ 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B.\ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ C.\ 2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D.\ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E.$ None of the above.

 

 

Question 6. Let $ABC$ be a triangle with area $1\ cm^2.$ Points $D,\ E,\ F$ lie on the sides $AB,\ BC,\ CA,$ respectively. Prove the

$min\left \{ S_{ADF};\ S_{BED};\ S_{CEF} \right \}\leq \frac{1}{4}\ cm^2$

 

 

Question 7. Let $ABC$ be a triangle with $\widehat{A}=90^{\circ},$ $\widehat{B}=60^{\circ},\ BC=1\ cm.$ Draw outside of $\bigtriangleup ABC,$ three equilateral triangle $ABD,\ ACE,\ BCF.$ Determine the area of $\bigtriangleup DEF.$

 

 

Question 8. Let $ABCDE$ be a convex pentagon. Given that $S_{ABC}= S_{BCD}=S_{CDE}= S_{DEA}= S_{EAB}=2\ cm^2.$ Find $S_{ABCDE}.$

 

 

Question 9. Solve the following  system in positive numbers

$\left\{\begin{matrix} x+y\leq 1\\ \frac{2}{xy}+\frac{1}{x^2+y^2}=10 \end{matrix}\right.$

 

 

Question 10. Consider the set of all rectangles with a given perimeter $p.$ Find the largest value of

$M=\frac{S}{2S+p+2}$

Where $S$ is denoted the area of the rectangle.

 

 

Question 11.  The positive numbers $a,\ b,\ c,\ d,\ e$ are such that the following identidy hold for all real number $x.$

$(x+a)(x+b)(x+c)=x^3+3dx^2+3x+e^3$

Find the smallest value of $d.$

 

 

Question 12. If $f(x)=ax^2+bx+c$ safisfies the condition

$|f(x)|<1,\ \forall\ x\in [-1,\ 1]$

Prove the the equation $f(x)=2x^2-1$ has two real roots.

 

 

Question 13. Solve the system of equations

$\left\{\begin{matrix} \frac{1}{x}+\frac{1}{y}=\frac{1}{6}\\ \frac{3}{x}+\frac{2}{y}=\frac{5}{6} \end{matrix}\right.$

 

 

Question 14. Solve the system of equations

$\left\{\begin{matrix} x^3+y=x^2+1\\ 2y^3+z=2y^2+1\\ 3z^3+x=3z^2+1 \end{matrix}\right.$

 

 

Question 15. Denote by $\mathbb{Q}$ and $\mathbb{N}^*$ the set of all rational and positive integer numbers, respectively. Suppose the $\frac{ax+b}{x}\in \mathbb{Q}$ for every $x\in \mathbb{N}^*.$ Prove that there exist integers $A,\ B,\ C$ such that

$\frac{ax+b}{x}=\frac{Ax+B}{Cx}$ for all $x\in \mathbb{N}^*$

 

___________

P/s: Do đi thi không được mang đề về, mình phải chép lại, có sai sót gì mong các bạn thông cảm.

Mấy bài trắc nghiệm giải ra luôn nha :))


Bài viết đã được chỉnh sửa nội dung bởi Hoang Huy Thong: 24-03-2013 - 18:44


#2
BlackSelena

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Nhân đây mình cũng nhắc luôn, vì đây là cuộc thi bằng tiếng Anh nên các bạn hãy trình bày lời giải bằng tiếng Anh nhé, coi như là luyện tập :) !



#3
duaconcuachua98

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Question $13$:

We have $\left\{\begin{matrix} \frac{1}{x}+\frac{1}{y}=\frac{1}{6} & \\ \frac{3}{x}+\frac{2}{y}=\frac{5}{6} & \end{matrix}\right. \Leftrightarrow \left\{\begin{matrix} \frac{1}{x}+\frac{1}{y}=\frac{1}{6} & \\ \frac{2}{x}+\frac{2}{y}+\frac{1}{x}=\frac{5}{6} & \end{matrix}\right. \Leftrightarrow \left\{\begin{matrix} \frac{1}{x}=\frac{3}{6} & \\ \frac{1}{y}=\frac{-2}{6} & \end{matrix}\right. \Leftrightarrow \left\{\begin{matrix} x=2 & \\ y=-3 & \end{matrix}\right.$



#4
ilovelife

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Q14:
$\left\{\begin{matrix} x^3+y=x^2+1\\ 2y^3+z=2y^2+1\\ 3z^3+x=3z^2+1 \end{matrix}\right.
\iff
\left\{\begin{matrix} x^3-x^2=1-y\\
2y^3-2y^2=1-z\\
3z^3-3z^2=1-x \end{matrix}\right.$

Case 1: $x=1 \implies y=z=1$

Case 2: $x>1 \implies 1-y=x^3-x^2>0 \iff 1>y  \\ \implies 2(y^3-y^2)=1-z<0 \iff z>1 \implies 1-x>0 \iff x<1 \implies \text{contradiction}$

Case 3: $x<1$, similar to Case 1, we get the contradiction

So, $x=y=z=1$

 

Q12:From the condition, we have:

$\left\{\begin{matrix}
|f(1)|=|a+b+c|<1\\
|f(-1)|=|a-b+c|<1\\
|f(0)|=|c|<1
\end{matrix}\right.$

$\implies 2>|f(1)|+|f(-1)|\ge 2|a+c| \iff |a+c|<1\ (1)$

Case 1: $0>c>-1 \implies a<2 \implies (a-2)(c+1)<0\ (1')$

Case 2: $1>c\ge 0 \implies a<1 \implies (a-2)(c+1)<0\ (1'')$

We also have: $f(x)=2x^2-1 \iff (a-2)x^2+bx + (c+1)=0\ (2)$

Combine (1),(1'),(1") and (2) $\implies f(x)=2x^2-1$ has 2 real root as required 

:lol: Tiếng anh mình không giỏi đâu


Bài viết đã được chỉnh sửa nội dung bởi ilovelife: 24-03-2013 - 20:32

God made the integers, all else is the work of man.

People should not be afraid of their goverment, goverment should be afraid of their people.

 


#5
namcpnh

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Có đề THPT không em?


Cùng chung sức làm chuyên đề hay cho diễn đàn tại :

Dãy số-giới hạn, Đa thức , Hình học , Phương trình hàm , PT-HPT-BPT , Số học.

Wolframalpha đây


#6
buiminhhieu

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Q9: we have $\frac{2}{xy}+\frac{1}{x^{2}+y^{2}}=\frac{1}{2xy}+\frac{1}{x^{2}+y^{2}}+\frac{3}{2xy}\geq \frac{4}{(x+y)^{2}}+\frac{3}{2.\frac{(x+y)^{2}}{4}}\geq 10$

Dấu = xảy ra $x=y=$$\frac{1}{2}$


%%- Chuyên Vĩnh Phúc

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#7
Nguyen Duc Thuan

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Senior Section
 
Question 1. How many three-digit perfect squares are there
such that if each digit is increased by one, the resulting number
is also a perfect square?
(A): 1; (B): 2; (C): 4; (D): 8; (E) None of the above.
 
Question 2. The smallest value of the function
$f(x) = \left | x \right |+\left | \frac{1-2013x}{2013-x} \right |$
where $x\in \left [ -1;1 \right ]$ is:
(A):$\frac{1}{2012}$       B: $\frac{1}{2013}$             C:$\frac{1}{2014}$           D: $\frac{1}{2015}$            (E): None of the above.                           
 
 Question 3. What is the largest integer not exceeding $8x^2+6x-1$
where $x=\frac{1}{2}\left ( \sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}} \right )$
(A): 1; (B): 2; (C): 3; (D): 4; (E) None of the above.

 

 

Question 4. Let $x_0=[\alpha ];x_1=[2\alpha ]-[\alpha ];x_2=[3\alpha ]-[2\alpha ];x_3=[4\alpha ]-[\alpha ]...$ 
where $\alpha =\frac{\sqrt{2013}}{\sqrt{2014}}$ .The value of $x_9$ is:
(A): 2; (B): 3; (C): 4; (D): 5; (E): None of the above.
 
Question 5. The number n is called a composite number if it
can be written in the form n = ab; where a; b are positive
integers greater than 1.
Write number 2013 in a sum of m composite numbers. What
is the largest value of m?
(A): 500; (B): 501; (C): 502; (D): 503; (E): None of the
above.

 

Em mới có bấy nhiêu, mn thông cảm!



#8
Zaraki

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Đáp án phần thi Junior và Senior

File gửi kèm


Discovery is a child’s privilege. I mean the small child, the child who is not afraid to be wrong, to look silly, to not be serious, and to act differently from everyone else. He is also not afraid that the things he is interested in are in bad taste or turn out to be different from his expectations, from what they should be, or rather he is not afraid of what they actually are. He ignores the silent and flawless consensus that is part of the air we breathe – the consensus of all the people who are, or are reputed to be, reasonable.

 

Grothendieck, Récoltes et Semailles (“Crops and Seeds”). 





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