chứng minh rằng với mọi ABC ta đều có:
http://dientuvietnam.net/cgi-bin/mimetex.cgi?\dfrac{a^2}{b+c-a}+\dfrac{b^2}{c+a-b}+\dfrac{c^2}{b+a-c}\geq3http://dientuvietnam.net/cgi-bin/mimetex.cgi?\sqrt{3}R
BẤt đẳng thức tam giác
Started By dungCT, 02-01-2006 - 14:30
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