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Member Since 04-07-2014
Offline Last Active 16-07-2014 - 19:54

04-07-2014 - 16:52

Giải hệ phương trình

$\left\{\begin{matrix}x^{2}+y^{2}=1 & & \\ \sqrt[1999]{x}-\sqrt[1999]{y}=(\sqrt[2000]{x}-\sqrt[2000]{y})(x+y+xy+2001) & & \end{matrix}\right.$

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