cuongmen78

cac bac giup toi bai nay voi

cho a,b,c $\geq 1$. tim GTNN cua bieu thuc P =$\frac{(a+1)(b+1)(c+1)}{abc+1}$

cho a,bc$\geqslant 1.tim gtln cuap P =\frac{\frac{(a+1)(b+1)(c+1)}{abc+1}}{}$

cho ab,c$\geqslant 1. tim gtln cua P= \frac{(a+1)(b+1)(c+1))}{abc+1}$

chờ a,b,c $\geqslant$1. Tìm Max của bieu thuc P=$\frac{(a+1)(b+1)(c+1)}{abc+1}$