Cho x,y,z > 0 thỏa mãn $x \geqslant y \geqslant z$
Chứng minh bất đẳng thức
$x\sqrt{x^2-xy+y^2}+y\sqrt{x^2-xz+z^2}+z\sqrt{y^2-yz+z^2} \geq x^2 + y^2 + z^2$
$x\sqrt{x^2-xy+y^2}+y\sqrt{x^2-xz+z^2}+z\sqrt{y^2-yz+z^2} \geq x^2 + y^2 + z^2$
Started By hoa_giot_tuyet, 18-08-2013 - 20:20
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