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$a^3+b^3+c^3+3abc \geq a^2\sqrt[3]{4(b^3+c^3)}+b^2\sqrt[3]{4(c^3+a^3)}+c^2\sqrt[3]{4(a^3+b^3)}$

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#1
mrjackass

mrjackass

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$a,b,c>0$. CMR: 

$a^3+b^3+c^3+3abc \geq a^2\sqrt[3]{4(b^3+c^3)}+b^2\sqrt[3]{4(c^3+a^3)}+c^2\sqrt[3]{4(a^3+b^3)}$


420 Blaze It Faggot





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