Cho $a,b,c>0$ thỏa $a+b+c=3$. CMR:
$\frac{a^2b}{1+a+b}+\frac{b^2c}{1+b+c}+\frac{c^2a}{1+c+a}\leq 1$
$\frac{a^2b}{1+a+b}+\frac{b^2c}{1+b+c}+\frac{c^2a}{1+c+a}\leq 1$
Started By HoangHungChelski, 19-08-2014 - 13:53
#1
Posted 19-08-2014 - 13:53
- shinichigl, Super Fields, hoangmanhquan and 3 others like this
#2
Posted 01-09-2014 - 09:14
Cho $a,b,c>0$ thỏa $a+b+c=3$. CMR:
$\frac{a^2b}{1+a+b}+\frac{b^2c}{1+b+c}+\frac{c^2a}{1+c+a}\leq 1$
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NTP
Edited by chardhdmovies, 03-09-2014 - 12:20.
- HoangHungChelski likes this
chúng tôi là 3 người từ lớp 10 cá tính:NRC,NTP,A-Q
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