Cho $(x-y)^{2}\leqslant(y-z)^{2}\leqslant(z-x)^{2}$
Chứng minh
$(x-y)^{2}\leqslant \frac{x^{2}+y^{2}+z^{2}}{2}$
Chứng minh $(x-y)^{2}\leqslant \frac{x^{2}+y^{2}+z^{2}}{2}$
Started By EvaristeGaloa, 02-09-2014 - 16:18
#2
Posted 02-09-2014 - 17:10
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