Cho a,b,c là 3 cạnh 1 tam giác thoã mãn $\sum a^{2}= 3$ CMR $\sum \frac{a}{(b+c-a)^{2}}\geq \frac{3}{a^{2}b^{2}c^{2}}$
$\sum \frac{a}{(b+c-a)^{2}}\geq \frac{3}{a^{2}b^{2}c^{2}}$
Started By trungdung97, 08-09-2014 - 20:08
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Posted 08-09-2014 - 20:08
trungdung97
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