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$\frac{a+b+c}{ab+bc+ca} \geq {}\sum \frac{a}{a^{2}+bc+b^{2}}$


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LumiseEdireKRN

LumiseEdireKRN

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Chứng minh rằng nếu a, b, c > 0 thì

$\frac{a+b+c}{ab+bc+ca} \geq {}\sum \frac{a}{a^{2}+bc+b^{2}}$


Kriestirst Riggel Night Lumise Edire.

Tran Le Kien Quoc - KGI - Vie.

 





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