Giải hệ phương trình:$\left\{\begin{matrix} x(x+y+1)-3=0 & & \\ (x+y)^2-\frac{5}{x^2+1}=0& & \end{matrix}\right.$
$\left\{\begin{matrix} x(x+y+1)-3=0 & & \\ (x+y)^2-\frac{5}{x^2+1}=0& & \end{matrix}\right.$
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Started By Xuan Hung HQH, 06-11-2014 - 17:17
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