cho a,b,c dương thoả $ab+bc+ca=3$ CMR
$\frac{1}{1+a^2(b+c)}+\frac{1}{1+b^2(c+a)}+\frac{1}{1+c^2(a+b)} \leq \frac{1}{abc}$
$\frac{1}{1+a^2(b+c)}+\frac{1}{1+b^2(c+a)}+\frac{1}{1+c^2(a+b)} \leq \frac{1}{abc}$
Started By zzhanamjchjzz, 05-01-2015 - 17:31
#2
Posted 05-01-2015 - 18:37
Dinh Xuan Hung
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