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$\left\{\begin{matrix} (x+6y+3)\sqrt{xy+3y}=(8y+3x+9)y & & \\ ... & & \end{matrix}\right.$

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#1
congdaoduy9a

congdaoduy9a

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Giải hệ pt : 

$\left\{\begin{matrix} (x+6y+3)\sqrt{xy+3y}=(8y+3x+9)y & & \\ \sqrt{-x^{2}+8x-24y+417}=(y+3)\sqrt{y-1}+3y+17 & & \end{matrix}\right.$

 



#2
phan huong

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Giải hệ pt : 

$\left\{\begin{matrix} (x+6y+3)\sqrt{xy+3y}=(8y+3x+9)y & & \\ \sqrt{-x^{2}+8x-24y+417}=(y+3)\sqrt{y-1}+3y+17 & & \end{matrix}\right.$

Từ pt (1)$\Rightarrow \sqrt{y}(2\sqrt{y}-\sqrt{x+3})(4y-\sqrt{y}\sqrt{x+3}+x+3)=0$

=>$2\sqrt{y}=\sqrt{x+3}\Leftrightarrow 4y=x+3$

thế vào (2) ..........


Edited by phan huong, 05-04-2015 - 21:10.





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