Tìm max: $a^{2}+ab+b^{2}-3a-3b+2002$
Max: $a^{2}+ab+b^{2}-3a-3b+2002$
Started By beanhdao01, 30-12-2015 - 19:54
#2
Posted 30-12-2015 - 20:01
dtthltvp
-
- Thành viên
-
- 39 posts
Binh nhất
Tìm max: $S=a^{2}+ab+b^{2}-3a-3b+2002$
$2S=2a^2+2ab+2b^2-3a-3b+4004=(a+b-1)^2+(a-0,5)^2+(b-0,5)^2+...$
Edited by dtthltvp, 30-12-2015 - 20:01.
#3
Posted 30-12-2015 - 20:07
leminhnghiatt
-
- Thành viên
-
- 1078 posts
Thượng úy
Tìm max: $a^{2}+ab+b^{2}-3a-3b+2002$
Đây là tim max hay min?
Don't care
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
