Giải phương trình: x2 + x + 2 - |x - 1| = 0
x2 + x + 2 - |x - 1| = 0
Started By phamquangnhatanh, 17-02-2016 - 21:00
#1
Posted 17-02-2016 - 21:00
#2
Posted 17-02-2016 - 21:05
Giải phương trình: x2 + x + 2 - |x - 1| = 0
Xét các $TH$:
$\ast )x<1\Rightarrow x^2+x+2+x-1=0\Rightarrow x^2+2x+1=0\Rightarrow (x+1)^2=0\Rightarrow x=-1(t/m)$
$\ast )x\geq 1\Rightarrow x^2+x+2-x+1=0\Rightarrow x^2+3=0(L)$
Vậy $x=-1$.
- tquangmh likes this
$\color{red}{\mathrm{\text{How I wish I could recollect, of circle roud}}}$
$\color{red}{\mathrm{\text{The exact relation Archimede unwound ! }}}$
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users