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$5x^{2}+5y^{2}+6xy-20x-20y+24=0$


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#1
phamquangnhatanh

phamquangnhatanh

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Tìm x, y nguyên thoả mãn:

$5x^{2}+5y^{2}+6xy-20x-20y+24=0$






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