$a,b,c\geq 0$ thỏa mãn $a+b+c=1$. Tìm max min $Q=\frac{1}{a+1}+\frac{1}{b+1}+\frac{1}{c+1}$
Edited by tpdtthltvp, 15-05-2016 - 22:57.
Tìm max min $Q=\frac{1}{a+1}+\frac{1}{b+1}+\frac{1}{c+1}$
Started By xuantungjinkaido, 15-05-2016 - 22:50
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Posted 15-05-2016 - 22:59
quangtohe
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Ta có:$\frac{1}{a+1}+\frac{1}{b+1}+\frac{1}{c+1}\geq \frac{9}{a+b+c+3}= \frac{9}{4}$
Dấu = xảy ra <=> $a= b= c= \frac{1}{3}$
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