Chứng minh rằng $\sum \sqrt{\frac{3a^{2}+1}{3b^{2}+1}}$ <= $\frac{7}{2}$
cho a+b+c=1
Started By xuantungjinkaido, 29-05-2016 - 17:59
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
Community Forum Software by IP.Board
Licensed to: Diễn đàn Toán học
