cho $x,y \geq 0$ thỏa mãn $x^{3}+y^{3} +xy=x^{2}+y^{2}$
TÌm min max $p= \frac{1+\sqrt{x}}{2+\sqrt{y}}+\frac{2+\sqrt{x}}{1+\sqrt{y}}$
Edited by tpdtthltvp, 05-09-2016 - 10:32.
cho $x,y \geq 0$ thỏa mãn $x^{3}+y^{3} +xy=x^{2}+y^{2}$
TÌm min max $p= \frac{1+\sqrt{x}}{2+\sqrt{y}}+\frac{2+\sqrt{x}}{1+\sqrt{y}}$
Edited by tpdtthltvp, 05-09-2016 - 10:32.
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