Giải phương trình
$\left ( 3x^2+3x-16 \right )^2=4\left ( 4-x^2 \right )\left ( 3-2x \right )^2$
$\left ( 3x^2+3x-16 \right )^2=4\left ( 4-x^2 \right )\left ( 3-2x \right )^2$
Started By The Flash, 22-09-2016 - 22:01
#2
Posted 22-09-2016 - 22:14
Baoriven
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- Điều hành viên OLYMPIC
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- 1425 posts
Thượng úy
Mình cứ phá ngoặc.
Phương trình tương đương: $(5x^2-16)(5x^2-6x-7)=0$.
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