Tìm các hàm $f$ tăng ($f:\mathbb{R}\rightarrow \mathbb{R}$) thỏa mãn:
$i)$ $f(0)=0;f(1)=1.$
$ii)$ $f(a)+f(b)=f(ab)+f(a+b-ab)$ với $\forall a,b\in \mathbb{R},a< 1< b.$
Edited by Baoriven, 15-01-2017 - 19:58.
$f:\mathbb{R}\rightarrow \mathbb{R}$: $f(a)+f(b)=f(ab)+f(a+b-ab)$
Started By Baoriven, 15-01-2017 - 19:48
#1
Posted 15-01-2017 - 19:48
Baoriven
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