tìm nghiệm nguyên dương pt $x^{3}(2x^{4}+3xy^{2}+10-2y)=3y^{3}+10y+1111$
$x^{3}(2x^{4}+3xy^{2}+10-2y)=3y^{3}+10y+1111$
Started By uchiha hitachi, 07-07-2017 - 21:27
1 user(s) are reading this topic
0 members, 1 guests, 0 anonymous users
Community Forum Software by IP.Board
Licensed to: Diễn đàn Toán học
