Cho $x\neq -2013$. Sử dụng bất đẳng thức Cauchy, chứng minh rằng:
$\frac{x}{(x+2013)^{2}}\leq \frac{1}{8052}$
Edited by Amasa, 01-08-2017 - 10:05.
Chứng minh $\frac{x}{(x+2013)^{2}}\leq \frac{1}{8052}$
Started By Amasa, 01-08-2017 - 10:00
#1
Posted 01-08-2017 - 10:00
Amasa
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Binh nhất
#2
Posted 01-08-2017 - 11:09
ngoisaouocmo
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$\Leftrightarrow \frac{1}{x+\frac{2013^2}{x}+4016}\leq \frac{1}{ 2 \sqrt{2013.2013}+4016}=\frac{1}{8052}$
Politics is for the present, but an equation is for eternity.
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