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$(x^2+y^2+z^2)^2>=3(x^{3}y+y^{3}z+z^{3}x)$


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#1
melodias2002

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CMR $(x^2+y^2+z^2)^2>=3(x^{3}y+y^{3}z+z^{3}x)$ với $x,y,z \in R$



#2
DOTOANNANG

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\[\left ( \sum x^{2} \right )^{2}\geq 3\left ( \sum x^{3}y \right )\]

\[\Leftrightarrow \sum \left ( 2x^{2}- y^{2}- z^{2}- xy+ yz \right )^{2}\geq 0\]






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