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$\sum \frac{\sqrt{x}}{\sqrt{yz}+\sqrt{3}}\leq \frac{1}{4\sqrt{3}xyz}$

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Khoa Linh

Khoa Linh

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Cho các số dương $x,y,z$ sao cho $xy+yz+zx=1$. Chứng minh rằng: 

$\frac{\sqrt{x}}{\sqrt{yz}+\sqrt{3}}+\frac{\sqrt{y}}{\sqrt{zx}+\sqrt{3}}+\frac{\sqrt{z}}{\sqrt{xy}+\sqrt{3}}\leq \frac{1}{4\sqrt{3}xyz}$


$\sqrt[LOVE]{MATH}$

"If I feel unhappy, I do mathematics to become happy. If I am happy, I

 

do mathematics to keep happy" - Alfréd nyi 





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