$\sqrt{3-x}+\sqrt{2+x}=x^3+x^2-4x-4+|x|+|x-1|$
Giai phuong trinh , $\sqrt{3-x}+\sqrt{2+x}=x^3+x^2-4x-4+|x|+|x-1|$
Started By trang2004, 25-08-2018 - 16:52
#2
Posted 26-08-2018 - 11:07
PhanThai0301
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$\sqrt{3-x}+\sqrt{2+x}=x^3+x^2-4x-4+|x|+|x-1|$
ĐKXĐ: $-2\leq x\leq 3$.
PT <=> $(x+2)(x-2)(x+1)+(\left | x-1 \right |-\sqrt{3-x})+(\left | x \right |-\sqrt{2+x})=0$
<=> $(x-2)(x+1)[x+2+\frac{1}{\left | x-1 \right |+\sqrt{3-x}}+\frac{1}{\left | x \right |+\sqrt{2+x}}]=0$
...sau bn tự lm nhá
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