Cho a,b,c>0 thoả mãn $a^{2}+b^{2}+c^{2}=3$
$\sqrt{\frac{a^{2}}{a^{2}+b+c}}+\sqrt{\frac{b^{2}}{b^{2}+a+c}}+\sqrt{\frac{c^{2}}{c^{2}+b+a}}\geq \sqrt{3}$
$\sum \sqrt{\frac{a^{2}}{a^{2}+b+c}} \geq \sqrt{3}$
Started By 01634908884, 14-09-2018 - 21:12
#1
Posted 14-09-2018 - 21:12
. Mây tầng nào gặp gió tầng ấy.
#2
Posted 15-09-2018 - 00:23
Cho a,b,c>0 thoả mãn $a^{2}+b^{2}+c^{2}=3$
$\sqrt{\frac{a^{2}}{a^{2}+b+c}}+\sqrt{\frac{b^{2}}{b^{2}+a+c}}+\sqrt{\frac{c^{2}}{c^{2}+b+a}}\geq \sqrt{3}$Đã có tại đây : https://diendantoanh...2a2bcleq-sqrt3/
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