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$a_{n+2}=6a_{n+1}-a_{n}-24(-1)^{n}$

Started By 01634908884, 18-09-2018 - 22:58

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Trung sĩ

Cho $a_{1}=6,a_{2}=14, và a_{n+2}=6a_{n+1}-a_{n}-24(-1)^{n}$
Tính lim $\sum_{1}^{n} \frac{1}{a_{k}}$

. Mây tầng nào gặp gió tầng ấy.

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