Giải phương trình: $\sqrt{x+2}+2\sqrt{4-x}=-3x+4\sqrt{(x-1)(2-x)}+16$
Edited by hangnguyen2003, 22-11-2018 - 00:59.
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Posted 22-11-2018 - 00:57
hangnguyen2003
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Posted 22-11-2018 - 20:52
buingoctu
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Giải phương trình: $\sqrt{x+2}+2\sqrt{4-x}=-3x+4\sqrt{(x-1)(2-x)}+16$
ĐK: $2\geq x\geq 1$
Xét $\sqrt{x-2}+2\sqrt{4-x}+3x=4\sqrt{(x-1)(2-x)}+16$
Có $\sqrt{x+2}+2\sqrt{4-x}+3x\leq \frac{x+2+1}{2}+4-x+1+3x=\frac{5x}{2}+5+\frac{5}{2}\leq 12,5$
VP (1) >12,5
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