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$$(abc+a+b+c)^{3}\geq 8abc(1+a)(1+b)(1+c)$$

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#1
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@HaiDangel  /   $a,b,c$ $>$ $0$, chứng minh rằng:

$$(abc+a+b+c)^{3}\geq 8abc(1+a)(1+b)(1+c)$$

 



#2
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$a,b,c$ $>$ $0$, chứng minh rằng:

$$(1+ab+bc+ca)^{3}\geq 8abc(1+a)(1+b)(1+c)$$



#3
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MichaelRozenberg.GIF

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