cho a,b,c là 3 số thực dương. Chứng minh rằng
$\sum \frac{ab}{a^{2}+ab+b^{2}}+1\geq \frac{4(ab+bc+ca)}{a^{2}+b^{2}+c^{2}+ab+bc+ca}$
Edited by darkangle249, 20-05-2021 - 22:07.
\sum \frac{ab}{a^{2}+ab+b^{2}}+1\geq \frac{4(ab+bc+ca)}{a^{2}+b^{2}+c^{2}+ab+bc+ca}
Started By darkangle249, 20-05-2021 - 22:05
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