Cho x, y, z, t là các số nguyên thỏa mãn $\left ( x-y-t \right )\left ( x-z-t \right )\left ( x+z-t \right )\left ( x+y+z-t \right )=210$
Tính $x+y-z+t$
Edited by Ngoc Hung, 29-09-2023 - 04:47.
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