Cho $a,b,c\geq 0: ab+bc+ca=1$. Chứng minh rằng
$$\frac{2a}{(a+1)^2} + \frac{2b}{(b+1)^2}+\frac{2c}{(c+1)^2} \geq \frac{2}{a+b+c}+\frac{abc}{2}$$
$\sum \frac{2a}{(a+1)^2} \geq \frac{2}{a+b+c}+\frac{abc}{2}$
Started By Duc3290, 02-04-2024 - 19:57
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