Giai he phuong trinh (an sox,y,z,t):
$x+y=3$
$xz+yt=4$
$xz^2+yt^2=6$
$xz^3+yt^3=10 $
Giai he phuong trinh!
Bắt đầu bởi NguyThang khtn, 04-11-2010 - 18:45
#1
Đã gửi 04-11-2010 - 18:45
It is difficult to say what is impossible, for the dream of yesterday is the hope of today and the reality of tomorrow
#2
Đã gửi 05-11-2010 - 16:18
x=2; y=1; z=1; t=2.Giai he phuong trinh (an sox,y,z,t):
$x+y=3$
$xz+yt=4$
$xz^2+yt^2=6$
$xz^3+yt^3=10 $
x=1; y=2; z=2; t=1.
Nothing is impossive.
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#3
Đã gửi 05-11-2010 - 18:25
cau co can to pót giai ko?
It is difficult to say what is impossible, for the dream of yesterday is the hope of today and the reality of tomorrow
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