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[loc1997]

- $\frac{2x}{3x^{2}-x+2}+\frac{-7x}{3x^{2}+7x+2}=1$
- $\frac{x^{2}+2}{x^{2}-2x+2}-\frac{x^{2}+2}{x^{2}+3x+2}=\frac{5}{2}$

[phantomladyvskaitokid]

- $\frac{2x}{3x^{2}-x+2}+\frac{-7x}{3x^{2}+7x+2}=1$
- $\frac{x^{2}+2}{x^{2}-2x+2}-\frac{x^{2}+2}{x^{2}+3x+2}=\frac{5}{2}$

* x=0 k la no
* $x\neq 0$
$\frac{2x}{3x^{2}-x+2}+\frac{-7x}{3x^{2}+7x+2}=1$

$\Leftrightarrow \frac{2}{3x+\frac{2}{x}-1}+\frac{-7}{3x+\frac{2}{x}+7}=1$

$\Leftrightarrow \frac{2}{a-1}-\frac{7}{a+7}=1$

...

cau kia tuong tu

Edited by phantomladyvskaitokid, 18-03-2012 - 18:16.